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Question

A moving coil galvanometer allows a full scale current of 104A. A series resistance of 2MΩ is required to convert the above galvanometer into a voltmeter of range 05V. therefore the value of shunt resistance required to convert the above galvanometer into an ammeter of range 010mA is:

A
40Ω
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B
100Ω
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C
10Ω
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D
500Ω
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Solution

The correct option is A 40Ω
s=[Ig2IIg]G
=(IIg)Ig=gs
I=Ig(Gs+1)
2IIg=2Ig(Gs)+Ig
200+104G=5
200G=5
2005=G
40Ω

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