A moving coil galvanometer has a coil of effective area $A$ and number of turns $N$ . The magnetic field $B$ is radial. If a current $I$ is passed through the coil, the torque acting on the coil is.

N A^{2} B^{2} I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N A B I^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N^{2} A B I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N A B I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $N A B I$
Let l and b be the length and breadth of the coil respectively. Effective area =A
If $θ$ is the angle formed by direction of magnetic field with normal drawn on the plane of coil , then
Torque $τ = N I B A sin θ$
With radial magnetic field $θ = 90$
$τ = N A B I$

Suggest Corrections

Similar questions

Q. A moving coil galvanometer has a coil of area A and number of turns N. A magnetic field B is applied on it. The torque acting on it is given by

τ = k i

where i is current through the coil. If moment of inertia of the coil is I about the axis of rotation.
If the value of k in terms of galvanometer parameters (N, B, A) is given by

k = x \times N B A

. Find x.

Moving coil galvanometer operates on Permanent Magnet Moving Coll (PMMC) mechanism.

Moving coil galvanometers are of two types
(a) Suspended coll
(b) Pivoted coil type or tangent galvanometer,

Its working is based on the fact that when a current carrying coil is placed in a magnetic field, it experiences a torque. This torque tends to rotate the coil about its axis of suspension in such a way that the magnetic flux passing through the coil is maximum.

$(i v)$ In a moving coil galvanometer, having a coil of $N$ -turns of area $A$ and carrying current $I$ is placed in a radial field of strength $B$ . The torque acting on the coil is