Question

A moving coil galvanometer has n=30, B=0.25 T, $A=1.5\times {10}^{-3}{m}^2$ and $C={10}^{-3}Nm/degree$. The current sensitivity of the galvanometer is

• A. 41.25 degree/A
• B. 31.25 degree/A
• C. 21.25degree/A
• D. 11.25 degree/A

Answer 1

The correct option is D 11.25 degree/A

$\frac{\theta }{i}=\frac{BAN}{C}=\frac{0.25\times 1.5\times {10}^{-3}\times 30}{{10}^{-3}}\frac{\theta }{i}=\frac{45}{4}=11.25degree/A$