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Question

A moving coil galvanometer is converted into an ammeter reading upto 0.03 A by connecting a shunt of resistance 4r across it and into an ammeter reading upto 0.06 A when a shunt of resistance r connected across it. What is the maximum current which can be sent through this galvanometer if no shunt is used.

A
0.01 A
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B
0.02 A
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C
0.03 A
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D
0.04 A
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Solution

The correct option is B 0.02 A
For ammeter, S=ig(iig)GigG=(iig)S
So igG=(0.03ig)4r .........(i) and igG=(0.06ig)r
Dividing equation (i) by (ii) 1=(0.03ig)40.06ig0.06ig=0.124ig
3ig=0.06ig=0.02 A

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