A moving coil galvanometer A has 100 turns and resistance 50Ω. Another moving coil galvanometer B has number of turns 500 and resistance 200Ω. The other quantities are same in both cases. They are connected by a battery of internal resistance of 50Ω respectively. The ratio of deflection of B to A is (Give integer value)
For a moving coil galvanometer, BiAN=Cθ
θ∝iN (Since, other quantities are same.)
For A:−
θA∝iANA
θA∝E(GA+r))NA …(1)
For B:−
θB∝E(GB+r))NB …(2)
From (1) and (2) we get,
θBθA=NBNA×(GA+r)(GB+r)
Substituting the data given in the question,
θBθA=500100×(50+50)(200+50)
=5×100250
=2
Accepted answer : 2