Question

A moving sidewalk in an airport terminal building moves at a speed of 1.0 $m{s}^{-1}$ and is 35.0 m long. If a woman steps on at one end and walks at 1.5 $m{s}^{-1}$ relative to the moving sidewalk, then find the time that she requires to reach the opposite end (a) when she walks in the same direction the sidewalk is moving and (b) when she walks in the opposite direction.

Answer 1

$V_{s}idewalk=V_{sw}=1m/s$ length$=d=35m{V}_w=1.5m/s$ relative to sidewalk

$a$ when woman walks in direction of sidewalk hell speed $V=V_{sw}+V_w=2.5m/s\therefore t=\frac{35}{25}\times 10=14seconds$

$b$ when she walks opposite to sidewalk hell speed with ground$V_w-V_{sw}=1.5-1=0.5m/s\therefore t=\frac{35}{5}\times 10=70seconds$