Question

Question 134

A multistory building has 25 floors above the ground level each of height 5 m. it also has 3 floors in the basement each of height 5m. A lift in building moves at a rate of $\frac{1m}{s}$. If a man starts from 50m above the ground, how long will it take him to reach 2nd floor of the basement?

Answer 1

Man covers the distance above the ground = 50 m
and man covers the distance below the ground = $2\times 5=10m$
[$\because$ distance between two floors = 5 m ]
Thus, total distance = 50 m + 10 m = 60 m

$\because$ Speed of the lift = 1 m/s
Hence, time taken to reach second floor of basement$=\frac{Distance}{Speed}=\frac{60m}{1m/s}=60s$ or 1min