A myopic person can not see objects lying beyond 2m. The focal length and power of the lens required to remove this defect will be
A
1 m and 0.5 D
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B
−2 m and −0.5 D
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C
0.5 m and 0.5 D
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D
−0.5 m and 0.5 D
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Solution
The correct option is B−2 m and −0.5 D u=+2m v=∞
use lens formula 1v−1u=1f
where u = distance of object v= distance of image f=focal length P=power
put the values 1∞−12=1f f=−2m P=1f=12=0.5D