A myopic person can not see objects lying beyond $2 m$ . The focal length and power of the lens required to remove this defect will be

1 m & 0.5 D

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- 2 m & - 0.5 D

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0.5 m & 0.5 D

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- 0.5 m & 0.5 D

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Solution

The correct option is B $- 2 m & - 0.5 D$
$v = - 2 m$
$u = - \infty$
Apply lens formula
$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
$\frac{1}{- 2} - \frac{1}{- \infty} = \frac{1}{f}$
$f = - 2 m$
$p = \frac{1}{f} = \frac{1}{- 2} = - 0.5 D$

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A myopic person can not see objects lying beyond 2 m. The focal length and power of the lens required to remove this defect will be

The correct option is B −2 m & −0.5 Dv=−2 m u=−∞ Apply lens formula 1v−1u=1f 1−2−1−∞=1f f=−2 m p=1f=1−2=−0.5 D

A myopic person can not see objects lying beyond $2 m$ . The focal length and power of the lens required to remove this defect will be

The correct option is B $- 2 m & - 0.5 D$
$v = - 2 m$
$u = - \infty$
Apply lens formula
$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
$\frac{1}{- 2} - \frac{1}{- \infty} = \frac{1}{f}$
$f = - 2 m$
$p = \frac{1}{f} = \frac{1}{- 2} = - 0.5 D$