A N-pole of a very long magnetic needle is placed at a distance of 20 cm from a point P. If the pole strength of the magnetic needle is 40 Am, the magnetic induction at the point P is

^{- 3}

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^{- 4}

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^{- 6}

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^{- 8}

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Solution

The correct option is C 10 $^{- 4}$ T
$m = 40 A m$
$d = 20 c m$
$B = \frac{μ_{0} m}{4 π d^{2}}$
$= \frac{10^{- 7} \times 100}{1^{2}}$
$B = 10^{- 4} T$

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