CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A) Na2O2+H2SO4Na2SO4+H2O2
1) Redox reaction
B) H2+Cl22HCl
2) Oxidation reaction
C) Cr(OH)3CrO24
3) Non - redox reaction
D) IO3I
4) Reduction reaction

A
A - 3, B - 1, C - 2, D - 4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
A - 3, B - 2, C - 1, D - 4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A - 1, B - 3, C - 2, D - 4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
A - 1, B - 3, C - 4, D - 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B A - 3, B - 1, C - 2, D - 4
A) Na2O2+H2SO4Na2SO4+H2O2
In the reaction of sodium peroxide with sulphuric acid, the oxidation numbers of all the species remains same. Hence, it is non-redox reaction.
B) H2+Cl22HCl
In the reaction of hydrogen with chlorine to form hydrogen chloride, hydrogen is oxidized and chlorine is reduced. Thus, it is a redox reaction.
C) Cr(OH)3CrO24
During conversion of chromium trihydroxide to chromate ion, the oxidation number of chromium changes from +3 to +6. Hence, chromium is oxidized.
D) IO3I
During conversion of IO3 to I, the oxidation number of iodine changes from +5 to -1. Thus, iodine is reduced in this reaction.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Position of Hydrogen in the Periodic Table
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon