Question

A nail has $2c{m}^2$ at one end and $\frac{1}{100}c{m}^2$ at the other end. A force of 1000 gwt is applied on the first end. Calculate the pressure acting on the wall?

• A. $78\times {10}^{6}dynec{m}^{-2}$
• B. $88\times {10}^{6}dynec{m}^{-2}$
• C. $98\times {10}^{6}dynec{m}^{-2}$
• D. $95\times {10}^{6}dynec{m}^{-2}$

Answer 1

The correct option is C $98\times {10}^{6}dynec{m}^{-2}$

Thrust acting $=$ force applied
$F=1000gwt$
The area of contact of the nail with the wall $\left(A\right)=1/100c{m}^2$
$Pressure=\frac{\text{Thrust acting}}{\text{Area of contact}}$
$\therefore P=\frac{1,000}{1/100}=(1000\times 100)$
$={10}^{5}gwtc{m}^{-2}(\because 1gwt=980dyne)$
$=980\times {10}^{5}dynec{m}^{-2}$
Therefore, pressure acting on the wall is $98\times {10}^{6}dynec{m}^{-2}$.