A namkeen mixture contains $250.785 g$ roasted chana, $225.802 g$ roasted moong and $300.005 g$ roasted peanuts. How many grams of roasted cornflakes should be added so that the weight of the mixture is $1 k g$ ?

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Solution

numkeen mixture
chana = 250.785 gm
moong = 225.802 gm
peanuts = 300. 005 gm
total mixture = 1 kg = 1000 gm
$∴$ chana + moong +peanuts+ cornflakes = 1000 gm
$∴ 250.785 + 225.802 + 300.005 + c o r n f l a k e s = 1000 g m$
$∴ c o r n f l a k e s = 1000 - 250.785 - 225.802 - 300.005$
$= 223.408 g m$

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A namkeen mixture contains 250.785 g roasted chana, 225.802 g roasted moong and 300.005 g roasted peanuts. How many grams of roasted cornflakes should be added so that the weight of the mixture is 1 kg?

numkeen mixturechana = 250.785 gmmoong = 225.802 gmpeanuts = 300. 005 gmtotal mixture = 1 kg = 1000 gm∴ chana + moong +peanuts+ cornflakes = 1000 gm∴250.785+225.802+300.005+cornflakes=1000gm∴cornflakes=1000−250.785−225.802−300.005=223.408gm

A namkeen mixture contains $250.785 g$ roasted chana, $225.802 g$ roasted moong and $300.005 g$ roasted peanuts. How many grams of roasted cornflakes should be added so that the weight of the mixture is $1 k g$ ?