A narrow slit of width 0-5 mm is illuminated by light of wavelength - - 450 nm- A screen is placed at 1-5 m- The distance between the first minimas on either side is

Gap between two first minimas nbsp; = 2 ( Dλ/d) = 2 ( 1.5 × 450 × 10^ 9/0.5 × 10^ 3) = 2 × 3 × 450 × 10^ 6 = 6 × 450 × 10^ 6 = 2700 × 10^ 6 nbsp; = 2.7 mm ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Angular Position of Fringes in Diffraction

A narrow slit...

Question

A narrow slit of width 0.5 mm is illuminated by light of wavelength $λ = 450$ nm. A screen is placed at 1.5 m. The distance between the first minimas on either side is

2.7 mm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.6 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.9 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.8 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 2.7 mm

Gap between two first minimas
$= 2 (\frac{D λ}{d})$
$= 2 (\frac{1.5 \times 450 \times 10^{- 9}}{0.5 \times 10^{- 3}})$
$= 2 \times 3 \times 450 \times 10^{- 6}$
$= 6 \times 450 \times 10^{- 6} = 2700 \times 10^{- 6}$
= 2.7 mm

Suggest Corrections

Similar questions

Q. A narrow slit of width 0.5 mm is illuminated by light of wavelength

λ = 450

nm. A screen is placed at 1.5 m. The distance between the first minimas on either side is

Q. A biprism is placed at a distance of 50 mm in front of a narrow slit illuminated by light of wavelength 600 nm . The virtual images formed by the biprism are 0.5 mm apart . Find the width of the fringes formed on a screen placed 0.75 m apart in front of the biprism.

Q. In a Fraunhofer diffraction experiment, a single slit of width

0.5 m m

is illuminated by a monochromatic light of wavelength

600 n m

. The diffraction pattern is observed on a screen at a distance of

50 c m

from the slit. What will be the linear separation of the first order minima?

Q. Monochromatic light from a narrow slit illuminates two narrow slits 0.3 mm apart, producing an interference pattern with bright fringes 1.5 mm apart on a screen 75 cm away. Find the wavelength of the light. Find the fringe width if (a) the distance of the screen is doubled and (b) the separation between the slits is doubled?

Q. A screen is placed 50 cm from a single slit which is illuminated with light of wavelength 6000

0 A

. If the distance between the first and third minima in the diffraction pattern is 3.0 mm, the width of the slit is

Join BYJU'S Learning Program

A narrow slit of width 0.5 mm is illuminated by light of wavelength λ=450 nm. A screen is placed at 1.5 m. The distance between the first minimas on either side is

The correct option is A 2.7 mm Gap between two first minimas =2(Dλd) =2(1.5×450×10−90.5×10−3) =2×3×450×10−6 =6×450×10−6=2700×10−6 = 2.7 mm

A narrow slit of width 0.5 mm is illuminated by light of wavelength $λ = 450$ nm. A screen is placed at 1.5 m. The distance between the first minimas on either side is

The correct option is A 2.7 mm

Gap between two first minimas
$= 2 (\frac{D λ}{d})$
$= 2 (\frac{1.5 \times 450 \times 10^{- 9}}{0.5 \times 10^{- 3}})$
$= 2 \times 3 \times 450 \times 10^{- 6}$
$= 6 \times 450 \times 10^{- 6} = 2700 \times 10^{- 6}$
= 2.7 mm