A nationalized bank has found that the daily balance available in its savings accounts follows a normal distribution with a mean of Rs. 500 and a standard deviation of Rs. 50. The percentage of savings account holders, who maintain an average daily balance more than Rs. 500 is ______.

50

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Solution

The correct option is A 50
$μ = 500$
$σ = 500$

So $Z_{x} = \frac{x - μ}{σ} = \frac{500 - 500}{50} = 0$

So $P (x > 500) = P (Z_{x} > 0) = 0.5 \approx 50 %$

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A nationalized bank has found that the daily balance available in its savings accounts follows a normal distribution with a mean of Rs. 500 and a standard deviation of Rs. 50. The percentage of savings account holders, who maintain an average daily balance more than Rs. 500 is ______. 50

The correct option is A 50μ=500 σ=500 So Zx=x−μσ=500−50050=0 So P(x>500)=P(Zx>0)=0.5≈50%

A nationalized bank has found that the daily balance available in its savings accounts follows a normal distribution with a mean of Rs. 500 and a standard deviation of Rs. 50. The percentage of savings account holders, who maintain an average daily balance more than Rs. 500 is ______.

50

The correct option is A 50
$μ = 500$
$σ = 500$

So $Z_{x} = \frac{x - μ}{σ} = \frac{500 - 500}{50} = 0$

So $P (x > 500) = P (Z_{x} > 0) = 0.5 \approx 50 %$