Question

# A natural no., when increased by 12 equals 160 times its reciprocal. Find the no.

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Solution

## Dear student, Following is the answer to your query: Let the number be n. According to the given condition the equation formed will be: n+12 = $\frac{160}{n}$ $⇒{n}^{2}+12n-160=0\phantom{\rule{0ex}{0ex}}⇒{n}^{2}+20n-8n-160=0\phantom{\rule{0ex}{0ex}}⇒n\left(n+20\right)-8\left(n+20\right)=0\phantom{\rule{0ex}{0ex}}⇒n=8,-20\phantom{\rule{0ex}{0ex}}$ Since, n is a natural so n cannot be -20 Hence, n=8

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