Question

A natural number, when increased by 12, becomes equal to 160 times its reciprocal. Find the number.

Answer 1

Let the number be $x$. Then,

$x+12=160\times \frac{1}{x}$

$x^2+12x-160=0$

$(x+20)(x-8)=0$

$x=-20,8$

Therefore, the required number is $8.$