Question

A natural number, when increased by 84, equs 160 times its reciprocal. Find the number

Answer 1

Let the natural number be N.
N is increased by 84. Hence, it becomes (N+84).
According to the question,
N+84=160(1/N) -------- equation 1.
Now we multiply the equation 1 by N, so we get
N^2+84N=160
=> N^2+84N-160=0
There are no natural numbers N such that this equation factorizes. Hence, the question has no solution.