Question

A natural number $x$ is random;y selected from the set of first $100$ numbers. Find the probability that it satisfies the inequality $x+\frac{100}{x}>50$

Answer 1

Total number of ways of selecting $x$ is $100$.

Acc to condition $x+\frac{100}{x}>50$

this equation will only be satisfied for $x>48,x=1\&2$ .

so favourable cases are $55.$

so probability is $\frac{55}{100}=\frac{11}{20}$