A Navidaya Vidyalaya has rectangular playground having length $1000 m$ and width $580 m$ . Find the ratios of width of playground to its length :

5 : 4

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\frac{29}{50}

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\frac{50}{29}

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\frac{29}{158}

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Solution

The correct option is C $\frac{29}{50}$
$\begin{matrix} L e n g t h o f p l a y g r o u n d = 1000 m W i d t h o f p l a y g r o u n d = 580 m N o w, R a t i o = \frac{w i d t h}{l e n g t h} = \frac{580}{1000} = \frac{29}{50} = 29 : 50 \end{matrix}$
Hence, we find the following ratio

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A Navidaya Vidyalaya has rectangular playground having length 1000 m and width 580 m. Find the ratios of width of playground to its length :

The correct option is C 2950Lengthofplayground=1000mWidthofplayground=580mNow,Ratio=widthlength=5801000=2950=29:50Hence, we find the following ratio

A Navidaya Vidyalaya has rectangular playground having length $1000 m$ and width $580 m$ . Find the ratios of width of playground to its length :

The correct option is C $\frac{29}{50}$
$\begin{matrix} L e n g t h o f p l a y g r o u n d = 1000 m W i d t h o f p l a y g r o u n d = 580 m N o w, R a t i o = \frac{w i d t h}{l e n g t h} = \frac{580}{1000} = \frac{29}{50} = 29 : 50 \end{matrix}$
Hence, we find the following ratio