A near ultraviolet photon of 300 nm is absorbed by a gas and then remitted as two photons. One photon is red with wavelength of 760 nm. What would be the wave number of the second photon?
A
2×106m−1
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B
2×104m−1
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C
2×105m−1
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D
2×1011m−1
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Solution
The correct option is A2×106m−1 Energy absorbed = Sum of energy of two quanta Since, E = hcλ hc300×10−9=hc760×10−9+hcλ 1300×10−9=1760×10−9+1λ On solving, we get λ=4.95×10−7 m Now, wave number −v = 1λ −v=1λ=2×106m−1