A near ultraviolet Photon of wavelength 300 nm is observed by a gas and then remitted as 2 photons.One Photon is red, wavelength of which is 760 nm. What would be the wavelength of second Photon in manometer?
E =hc/λ
Wavelength of 1st photon = λ1
Wavelength of 2nd photon = λ2
E(Total) = E1 + E2 = Emitted energy
hc/ λ = hc/ λ1 + hc/ λ2
1/300 = 1/760 + 1/ λ2
1/ λ2 = (1/300 – 1/760)
λ2 = 496 nm = wavelength of second photon