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Byju's Answer
Standard X
Mathematics
Solving a Quadratic Equation by Factorization Method
A negative ...
Question
A negative
π
−
m
e
s
o
n
at rest can decay as
π
−
→
μ
−
+
v
. Then the energy of
μ
−
A
can be anything
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B
is a fixed quantity
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C
is zero
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D
is equal to 2
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Solution
The correct option is
B
is a fixed quantity
Energy of muon
(
μ
−
)
is a fixed quantity. It has rest energy of
108
M
e
V
.
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