Question

A neon dioxygen mixture contains 70.6 gram dioxygen and 167.5 gram neon. If pressure of the mixture of gases in the cylinder is 25 bar. What is the partial pressure of dioxygen and neon in the mixture ?

Answer 1

Partial pressure = mole fraction of given gas × purepure pressure.


Mole fraction = Number of moles of given gas / total number of moles.

Mole of dioxygen in mixture = given mass of dioxygen / molecular mass of dioxygen
= 70.6 g/ 32 g = 2.2 moles

Moles of Neon in mixture = given mass of neon / atomic mass of neon
= 167.5 g / 20 = 8.3 moles.

total number of moles = 2.2 + 8.3 = 10.5 mole

mole fraction of O2 = 2.2 / 10.5 = 0.2

Mole fraction of neon = 8.3/ 10.5 = 0.8

partial pressure of di oxygen = 0.2 × 25 = 5 bar

Partial pressure of neon =0.8 × 25 = 20 bar