A net force F is required to give an object with mass m an acceleration a. If a net force 6F is applied to an object with mass 2m, what is the acceleration on this object?

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Solution

The correct option is C
3a

We know that, net force = mass $\times$ acceleration

As per the question, $F = m a$

Now, when a force $6 F$ is applied to a body of mass $2 m$ , let the acceleration be $a^{'}$ .

So, $6 F = 2 m \times a^{'}$

$\Rightarrow a^{'} = 3 \frac{F}{m} = 3 a$

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A net force F is required to give an object with mass m an acceleration a. If a net force 6F is applied to an object with mass 2m, what is the acceleration on this object?

The correct option is C 3a We know that, net force = mass × acceleration As per the question, F=ma Now, when a force 6F is applied to a body of mass 2m, let the acceleration be a′. So, 6F=2m×a′ ⇒a′=3Fm=3a

The correct option is C
3a

We know that, net force = mass $\times$ acceleration

As per the question, $F = m a$

Now, when a force $6 F$ is applied to a body of mass $2 m$ , let the acceleration be $a^{'}$ .

So, $6 F = 2 m \times a^{'}$

$\Rightarrow a^{'} = 3 \frac{F}{m} = 3 a$