Question

A network of four capacitors of $6\mu F$ each is connected to a $240V$ supply. Determine the charge on each capacitor.

Answer 1

$\frac{1}{C^{\prime }}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{3}{6}=\frac{1}{2}$
$\Rightarrow$ $C^{\prime }=2\mu F$
Now, total $C=6+2=8\mu F$
$\because$ $q=CV$
$\Rightarrow$ $=2\times {10}^{-6}\times 240$
$\Rightarrow$ $q=4.8\times {10}^{-4}$ coulomb

On each of $6\mu F$ capacitor in series i.e., $C_1,C_2$ and $C_3$
Again,
$q=CV$
$=6\times {10}^{-6}\times 240$
$=1.44\times {10}^{-3}$ Coulomb in $C_4$