A network of uncharged capacitors and resistance is as shown. Current through the battery immediately after key $k$ is closed and after a long time interval is

\frac{E}{R_{1}}, \frac{E}{R_{1} + R_{3}}

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\frac{E}{R_{1} + R_{3}}, \frac{E}{R_{1} + \frac{R_{2} R_{3}}{R_{2} + R_{3}}}

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Z e r o, \frac{E}{R_{1}}

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\frac{E}{R_{1} + \frac{R_{2} R_{3}}{R_{2} + R_{3}}}, \frac{E}{R_{1}}

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Solution

The correct option is A $\frac{E}{R_{1}}, \frac{E}{R_{1} + R_{3}}$
At t = 0; resistance offered by $C_{1} a n d C_{2}$ is 0
So $i_{t = 0} = \frac{E}{R_{1}}$
and after long time, resistance offered by $C_{1} a n d C_{2} i s \infty$ So,
$i_{t = \infty} = \frac{E}{R_{1} + R_{3}}$

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Similar questions

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Table 1	Table - 2
(a) current through $R_{1}$	(p) E/R
(b) current through $R_{2}$	(q) 2E/R
(c) current through $R_{3}$	(r) E/2R
	(s) Zero

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A network of uncharged capacitors and resistance is as shown. Current through the battery immediately after key k is closed and after a long time interval is

The correct option is A ER1,ER1+R3At t = 0; resistance offered by C1 and C2 is 0 So it=0=ER1 and after long time, resistance offered by C1 and C2 is ∞ So, it=∞=ER1+R3

A network of uncharged capacitors and resistance is as shown. Current through the battery immediately after key $k$ is closed and after a long time interval is

The correct option is A $\frac{E}{R_{1}}, \frac{E}{R_{1} + R_{3}}$
At t = 0; resistance offered by $C_{1} a n d C_{2}$ is 0
So $i_{t = 0} = \frac{E}{R_{1}}$
and after long time, resistance offered by $C_{1} a n d C_{2} i s \infty$ So,
$i_{t = \infty} = \frac{E}{R_{1} + R_{3}}$