Question

A neutral atom has $2K$ electrons, $8L$ electrons and $6M$ electrons. Predict from this:
(a) its atomic number, (b) total number of $s$-electrons, (c) total number of $p$-electrons, (d) total number of $d$-electrons.

Answer 1

(a) Total number of electrons $=(2+8+6)=16$

So, Atomic number $=16$

Electronic configuration $=1s^2,2s^{2}2p^6,3s^{2}3p^4$

(b) Total number of $s$-electrons $=(1s^2+2s^2+3s^2)=6$

(c) Total number of $p$-electrons $=(2p^6+3p^4)=10$

(d) Total number of $d$-electrons $=0$.