Question

A neutral atom of an element has a nucleus with nuclear charge $11$ times and mass $23$ times that of hydrogen. Find the ratio of no. of electrons to protons present in its stable ion.

• A. $1:1$
• B. $5:6$
• C. $10:11$
• D. $12:11$

Answer 1

The correct option is C $10:11$

Hydrogen atom has nuclear charge of +1 and mass of 1.
Hence, the given neutral atom of an element has a nucleus with nuclear charge $11\times 1=11$, and nuclear mass $23\times 1=23$.
Now, we know that it is none other than Na atom.
The element can form a stable charged ion by losing 1 electron so that it attains stable electronic configuration of $Ne$ noble gas.
Number of electrons in neutral $sodium$ atom $=$ number of protons $=11$
Number of electrons in $N{a}^{+}$ ion $=11-1=10$.
The ratio of electrons to protons present in its stable ion will be $10:11$.

Hence, the correct option is C .