A neutral atom will have lowest ionization potential when its electronic configuration is?

1 s^{1}

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1 s^{2}, 2 s^{2}, 2 p^{6}

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1 s^{2}, 2 s^{2}, p^{2}

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1 s^{2}, 2 s^{2}, p^{6}, 3 s^{1}

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Solution

The correct option is C $1 s^{2}, 2 s^{2}, p^{2}$
(A) represents H atom which has a very high I.E.
(B) and (D) represents Inert gases which have very high I.Es
(C) represent Carbon family which can donate an electron with much ease as compared to the others.

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A neutral atom will have lowest ionization potential when its electronic configuration is?

The correct option is C 1s2,2s2,p2(A) represents H atom which has a very high I.E.(B) and (D) represents Inert gases which have very high I.Es(C) represent Carbon family which can donate an electron with much ease as compared to the others.

The correct option is C $1 s^{2}, 2 s^{2}, p^{2}$
(A) represents H atom which has a very high I.E.
(B) and (D) represents Inert gases which have very high I.Es
(C) represent Carbon family which can donate an electron with much ease as compared to the others.