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Standard XII

Physics

Magnetic Field

A neutral par...

Question

A neutral particle is at rest in a uniform magnetic field $\to B$ . At time t=0 it decays into two charged particles,each of mass m.The two particles move off in seperate paths,both of them lie in the plane perpendicular to $\to B$ . At a later time the particles collide.Express the time from decay until collison in terms of m,B and q.

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Solution

Since the particles are identical, they will have same time period for the revolution.
Also since they move in opposite directions initially, they would travel in the same circle in different directions.
Hence the time until they collide is equal to half the time period of individual particles.
Hence $t = \frac{T}{2} = \frac{π m}{q B}$

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