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Question

A neutron, a proton, an electron and an α particle enter a region of constant magnetic field with equal velocity. The B is along the perpendicularly inward to the plane of the paper. The path followed by each particle is shown in the figure.


The path followed by α particle is represented by:

A
B
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B
A
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C
D
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D
C
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Solution

The correct option is A B
The charge on the neutron, qn=0

From relation,

F=q(V×B)

Fn=0

Hence, it will go undeviated, represented by path C.

And we know that electron has negative charge so it will follow path D opposite to A & B.

Now rest of the charged particle will move on a circular path, whose radius is;

r=mvqB

For same value of V and B as mention in question,

rmq ....(1)

mα=4mp; qα=2qp

rαrp=mαqαqpmp=4mp2qpqpmp=2

rα>rp

Both of these positive charge will move/deviate in the same sense.
Hence, path A and B represent moment of proton and α particle.

rB>rA

Therefore, B represents path of αparticle.

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