Question

A neutron , a proton, an electron and an $\alpha$ particle enter perpendicular uniform magnetic field, with the same uniform velocity. The path of electron in the following figure will be :

• A. $4$
• B. $3$
• C. $2$
• D. $1$

Answer 1

The correct option is A $4$

The neutron goes undeflected, the $\alpha$ and proton being both positively charged moves towards left and electron being negatively charged moves towards right. or we can also use right hand to find the direction of force using formula $F=q(V\times B)$ but it moves right as $q$ is $-ve.$