A neutron is moving with velocity $u$ . It collides head on and elastically with an atom of mass number $A$ . If the initial kinetic energy of the neutrons is $E$ , then how much kinetic energy will be retained by the neutron after collision.

{(\frac{A}{A + 1})}^{2} E

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\frac{A}{{(A + 1)}^{2}} E

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{(\frac{A - 1}{A + 1})}^{2} E

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(\frac{A - 1}{{(A + 1)}^{2}}) E

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Solution

The correct option is C ${(\frac{A - 1}{A + 1})}^{2} E$
Fraction retained by nucleus
${(\frac{Δ k}{k})}_{r e t a i n e d} = {(\frac{m_{2} - m_{1}}{m_{1} + m_{2}})}^{2} = {(\frac{A - 1}{A + 1})}^{2}$
After collision kinetic energy retained by neutron ${(\frac{A - 1}{A + 1})}^{2} E$

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A neutron is moving with velocity u. It collides head on and elastically with an atom of mass number A. If the initial kinetic energy of the neutrons is E, then how much kinetic energy will be retained by the neutron after collision.

The correct option is C (A−1A+1)2EFraction retained by nucleus(Δkk)retained=(m2−m1m1+m2)2=(A−1A+1)2After collision kinetic energy retained by neutron (A−1A+1)2E

A neutron is moving with velocity $u$ . It collides head on and elastically with an atom of mass number $A$ . If the initial kinetic energy of the neutrons is $E$ , then how much kinetic energy will be retained by the neutron after collision.

The correct option is C ${(\frac{A - 1}{A + 1})}^{2} E$
Fraction retained by nucleus
${(\frac{Δ k}{k})}_{r e t a i n e d} = {(\frac{m_{2} - m_{1}}{m_{1} + m_{2}})}^{2} = {(\frac{A - 1}{A + 1})}^{2}$
After collision kinetic energy retained by neutron ${(\frac{A - 1}{A + 1})}^{2} E$