A neutron moving with a constant speed passes two points $3.6 m$ apart in 1.8*10^-4 seconds, the kinetic energy of the neutron is:-

Open in App

Solution

Speed of the neutron will be $v = \frac{3.6 m e t e r}{1.8 \times 10^{- 4} s} = 2 \times 10^{4} m / s$
Kinetic energy $K E = \frac{m v^{2}}{2}$ ,
put mass of neutron as $m = 1.67 \times 10^{- 27} K g$ with value $v$ as above,
we will get $K E = 3.34 \times 10^{- 19} j o u l e = \frac{3.34 \times 10^{- 10}}{1.6 \times 10^{- 19}} e V = 2.0875 e V$

Suggest Corrections

Similar questions

Q. A neutron, one of the constituents of a nucleus, is found to pass two points

60

meters apart in a time interval of

1.8 \times 10^{- 4}

sec. The mass of a neutron is

1.7 \times 10^{- 27}

kg. Assuming that the speed is constant, its kinetic energy is:

Q. A neutron, one of the constituents of a nucleus, is found to pass two points 60 metres apart in a time interval of

1.8 \times 10^{- 4} s e c

. The mass of the neutron is

1.67 \times 10^{- 27} k g

. Assuming that the speed is constant, its kinetic energy is

A bullet of mass $20 g$ is found to pass two points $30 m$ apart in a time interval of $4$ seconds. Calculate the kinetic energy of the bullet if it moves with constant speed.

Q. A moving neutron collides with a stationary

α - p a r t i c l e

. The fraction of the kinetic energy lost by the neutron is

Q. A neutron moving with velocity

u

, collides elastically with an atom of mass number

A

. If the collision is head on and the kinetic energy of neutron is

E

, then the final kinetic energy of neutron after collision is

Join BYJU'S Learning Program

A neutron moving with a constant speed passes two points 3.6m apart in 1.8*10^-4 seconds, the kinetic energy of the neutron is:-

Speed of the neutron will be v=3.6meter1.8×10−4s=2×104m/sKinetic energy KE=mv22,put mass of neutron as m=1.67×10−27Kg with value v as above,we will get KE=3.34×10−19joule=3.34×10−101.6×10−19eV=2.0875eV

A neutron moving with a constant speed passes two points $3.6 m$ apart in 1.8*10^-4 seconds, the kinetic energy of the neutron is:-