A neutron moving with a speed $^{'} v^{'}$ makes a head-on collision with a hydrogen atom in the ground state kept at rest. The minimum kinetic energy of the neutron for which inelastic collision will take place is (assume that mass of photon is nearly equal to the mass of neutron)

10.2 e V

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20.4 e V

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12.1 e V

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16.8 e V

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Solution

The correct option is B $20.4 e V$
In inelastic collision, energy gets transferred from one to other.
The minimum energy, hence, required is $10.2 e V$ which is sufficient for transition to $2^{n d}$ energy level, which requires kinetic energy of $2 \times 10.2 e V$
$\Rightarrow 20.4 e V$

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Similar questions

Q. A neutron moving with speed

v

makes a head-on collision with a hydrogen atom in ground state kept at rest. Find the minimum kinetic energy of the neutron for which inelastic (completely or partially) collision may take place. The mass of neutron

\approx

mass of hydrogen

= 1.67 \times 10^{- 27} k g

Q. A neutron moving with a speed

v

makes a head on collision with a hydrogen atom in ground state kept at rest. The minimum kinetic energy of neutron for which inelastic collision will take place is

Q. A neutron moving with a speed

^{'} v^{'}

makes a head on collision with a stationary hydrogen atom in ground state. The minimum kinetic energy of the neutron for which inelastic collision will take place is:

A neutron moving witha speed v strikes a hydrogen atom in ground state towards it with the same speed. Find the minimum speed of the neutron for which inelastic (completly or partially) collision may take place. The mass of neutron = mass of hydrogen = $1.67 \times 10^{- 27} k g$

Q. A neutron moving with a speed υ strikes a hydrogen atom in ground state moving towards it with the same speed. Find the minimum speed of the neutron for which inelastic (completely or partially) collision may take place. The mass of neutron = mass of hydrogen = 1.67 × 10⁻²⁷ kg.

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A neutron moving with a speed ′v ′ makes a head-on collision with a hydrogen atom in the ground state kept at rest. The minimum kinetic energy of the neutron for which inelastic collision will take place is (assume that mass of photon is nearly equal to the mass of neutron)

The correct option is B 20.4 eVIn inelastic collision, energy gets transferred from one to other. The minimum energy, hence, required is 10.2 eV which is sufficient for transition to 2nd energy level, which requires kinetic energy of 2×10.2 eV⇒20.4 eV

A neutron moving with a speed $^{'} v^{'}$ makes a head-on collision with a hydrogen atom in the ground state kept at rest. The minimum kinetic energy of the neutron for which inelastic collision will take place is (assume that mass of photon is nearly equal to the mass of neutron)

The correct option is B $20.4 e V$
In inelastic collision, energy gets transferred from one to other.
The minimum energy, hence, required is $10.2 e V$ which is sufficient for transition to $2^{n d}$ energy level, which requires kinetic energy of $2 \times 10.2 e V$
$\Rightarrow 20.4 e V$