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Question

A neutron star of enormous density is rotating at the rate of one rotation per second. If theradius of the star is 20km, then the acceleration in m/s2 units for any particle situated at the equator of the star will be (π210)

A
8×105
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B
20×103
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C
12×106
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D
4×108
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Solution

The correct option is A 8×105
Given : Frequency of rotation f=1 rps R=20km=20000 m
Angular velocity w=2πf=2π×1=2π rad/s
Centripetal acceleration of the particle at equator a=Rw2=R×4π2=20000×4×10=8×105 m/s2

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