Current price of the
car, Po=Rs360000
Rate of depreciation, 10% for first 2 years, 20%
for the third year
Now, Let price after 2 years= P
Thus, P=Po(1+R100)T
P=360000(1+−10100)2
P=360000×9×910×10
P=291600
After the third year, let the price be P′
P′=P(1+R′100)T
P′=291600(1+−20100)1
P′=291600×80100
P′=233280
Thus, the car will cost Rs 233280 after three years.