A non conducting ring of radius R has uniformly distributed positive charge Q. A small part of the ring, of length d, is removed (d<<R). The electric field at the centre of the ring will now be
A
directed towards the gap, inversely proportional to R3
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B
directed towards the gap, inversely proportional to R2
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C
directed away from the gap, inversely proportional to R3
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D
directed away from the gap, inversely proportional to R2
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Solution
The correct option is A directed towards the gap, inversely proportional to R3 If we fill the gap then there will be no electric field at the center of ring This signifies that electric field due to rest ring is equal to electric field due to gap and opposite in direction so electric field due to gap=KqR2 q=Qd2πR thus electric field E=KQdR3 Hence E will be inversely proportional to R3 and direction will be toward the gap