Question

A non-conducting sphere with a cavity has volume charge density $\rho$. $O_1$ and $O_2$ represent the two centres as shown. The electric field inside the cavity is $E_0$. Now, an equal and opposite charge is given uniformly to the sphere on its outer surface. The magnitude of electric field inside the cavity becomes

• A. Zero
• B. $E_0$
• C. $2E_0$
• D. $3E_0$

Answer 1

The correct option is C $2E_0$

$E_{+}=\frac{\rho }{3{ϵ}_0}{\overline{r}}_1$

now, $r$ $\alpha$ $2I$

now $E=2I$