A non-ideal gas follows van der Walls' gas equation, if x moles of a given gas is kept at a higher pressure, then:

x = \frac{P V}{R T + P b}

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P = \frac{x R T}{V - b}

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V = \frac{x R T}{P + \frac{a x^{2}}{V}}

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P V = x R T + P b

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Solution

The correct option is A $x = \frac{P V}{R T + P b}$
van der Walls' gas equation
$(P + \frac{a n^{2}}{V^{2}}) (V - n b) = n R T$
at high pressures,
$P >>> \frac{a n^{2}}{V^{2}}$
so the equation becomes,
$(P) (V - n b) = n R T$
after putting value of number of mole
$(P) (V - x b) = x R T$
$x = \frac{P V}{R T + P b}$

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