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Question

A non-planar loop of conducting wire carrying a current I is placed as shown in the figure. Each of the straight sections of the loop is of length 2a. The magnetic field due to this loop at the point P (a,0,a) point in the direction
1027099_22888211f6844d92abc0ec98ddab020a.png

A
12(^j+^k)
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B
13(^j+^k+^i)
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C
13(^i+^j+^k)
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D
12(^i+^j)
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Solution

The correct option is D 12(^i+^j)
The magnetic field at P(a,0,a) due to the loop is equal to the vector sum of the magnetic fields produced by loops ABCDA and AFEBA as shown in the figure.

Magnetic field due to loop ABCDA will be along ^i and due to loop AFEBA, along ^k. The magnitude of the magnetic field due to both the loops will be equal.

Therefore, direction of resultant magnetic field at P will be
12(^i+^k)

1725418_1027099_ans_b20d942f37294ef4b79c5265f72502f8.png

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