wiz-icon
MyQuestionIcon
MyQuestionIcon
9
You visited us 9 times! Enjoying our articles? Unlock Full Access!
Question

A non-relativistic positive charge particle of charge q and mass m is projected perpendicular to uniform magnetic field B as shown. Neglecting gravity, calculate xcoordinate of point on screen at which the charge particle will hit : d=R32, where R=mVqB


A
3R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2R
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
The particle describes a helical path of radius R=mvsinαqB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
The particle describes a circular path of radius R=mvqB
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D The particle describes a circular path of radius R=mvqB
Since it is given that motion of the charged particle is perpendicular to the magnetic field, the particle describes a circular path of radius, R=mVqB
From figure,
sinθ=dR=32
θ=60
The required x coordinate where the charge will hit is
x=(RRcosθ)+dcot30
x=R2+R32×3=2R

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Charge Motion in a Magnetic Field
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon