CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A non-viscous liquid is flowing through a non-uniform pipe from section A to section B as shown in the following figure. Cross-sectional area of the pipe at A is less than that at B. Which of the following statements are correct?

A
The pressure at A is greater than that at B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Velocity at A is greater than that at B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Total energy per unit volume of the liquid is greater at A than at B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Axis of the pipe cannot be horizontal
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A The pressure at A is greater than that at B
B Velocity at A is greater than that at B
D Axis of the pipe cannot be horizontal
Since liquid is flowing from A to B, hence, PA>PB.
According to equation of continuity
a1v1=a2v2
As, a2>a1, hence v1>v2
As the liquid is non-viscous, there is not loss of energy, i.e., energy per unit volume of the liquid is same at every point.
So, (c) is wrong.
Here, PA>PB, vA>vB and energy/volume of liquid is same at every point. So (PE)A<(PE)B.
Hence, section A must be at lower level than section B, i.e., pipe cannot be horizontal.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Bernoulli's Principle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon