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Question

A non zero polynomial f(x) with real coefficients satisfy f(x) = f(x)f′′(x) and f(0) = 96. If 'a' is the coefficient of highest degree term of f(x), then

A
a=118
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B
f1(6)=6
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C
f11(3)=5
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D
f(1)=10
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Solution

The correct options are
A a=118
C f11(3)=5
Let degree of f(x) be n.
n=(n1)+(n2)n=3
Hence f(x) =ax3+bx2+cx+96[f(0)=96]
Apply f(x) = f(x).f′′(x)a=118,b=2,c=24

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