wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

A non-zero vector a is parallel to the line of intersection of plane p1 determined by ^i+^j and ^i and plane P2 determined by vectors ^i^j and ^i+^k, then angle between a and vector ^i2^j+2^k is

A
π4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
π2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
π3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3π4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A π4
D 3π4

Equation of the plane containing ^i and ^i+^j is

[(r^i)^i(^i+^j)]=0

(r^i).[^i×(^i+^j)]=0

{(x^i+y^j+z^k)^i}.[^i×^i+^i×^j]=0

{(x1)^i+y^j+z^k}.[^k]=0(x1)^i.^k+y^j.^k+z^k.^k=0

z=0 ...(i)

Equation of the plane containing ^i^j and ^i+^k is

[(r(^i^j))(^i^j)(^i+^k)]=0

(r^i+^j).[(^i^j)×(^i+^k)]=0

{(x^i+y^j+z^k)(^i^j)}.[^i×^i+^i×^k^j×^i^j×^k]=0

{(x1)^i+(y+1)^j+z^k}.[^j+^k^i]=0

(x1)(y+1)+z=0...(ii)

Let a=a1^i+a2^j+a3^k

Since, a is parallel to Eqs. (i) and (ii), we obtain

a3=0

And a1+a2a3=0 a1=a2,a3=0

Thus, vector in the direction a is ^i^j

If θ is the angle between a and ^i2^j+2^k, then

cosθ=±(1)(1)+(1)(2)1+11+4+4=±32.3

cosθ=±12θ=π4or3π4


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What Is an Acid and a Base?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon