Question

A non-conducting ring of radius $R$ has charge $Q$ distributed unevenly over it. If it rotates with an angular velocity $\omega$, the equivalent current will be

Answer 1

Step 1: Given data

1. A non-conducting ring of radius $R$
2. Charge $Q$
3. Angular velocity $\omega$

Step 2: Formula used

1. $I=\frac{Q}{T}$ where $Q$ is the charge, $T$ is the time and $I$ is the current
2. $T=\frac{2\pi }{\omega }$ where $T$ is the time period and $\omega$ is the angular velocity

Step 3: Find the current

Given that $R$ is the non-conducting ring's radius $Q$ is the charge that has an asymmetric distribution throughout the ring.

It rotates with an angular speed that is determined by.
The charge's rotational period is determined by the formula $T=\frac{2\pi }{\omega }$
We've already stated that the amount of charges passing through any fixed place each second is the definition of current $I=\frac{Q}{T}$ is the formula used to calculate current.
The charge in this case is $Q$, and the time period is $T$.
We obtain $I=\frac{Q\omega }{2\pi }$ by inserting all the known values into the aforementioned equation.
Hence the equivalent current will be $\frac{Q\omega }{2\pi }$