Question

A non-conducting ring of radius $R$ has charge $Q$ distributed unevenly over it. If it rotates with an angular velocity $\omega$, the equivalent current will be

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Solution

Step 1: Given dataA non-conducting ring of radius $R$Charge $Q$ Angular velocity $\omega$Step 2: Formula used$I=\frac{Q}{T}$ where $Q$ is the charge, $T$ is the time and $I$ is the current $T=\frac{2\pi }{\omega }$ where $T$ is the time period and $\omega$ is the angular velocityStep 3: Find the current Given that $R$ is the non-conducting ring's radius $Q$ is the charge that has an asymmetric distribution throughout the ring. It rotates with an angular speed that is determined by.The charge's rotational period is determined by the formula $T=\frac{2\pi }{\omega }$We've already stated that the amount of charges passing through any fixed place each second is the definition of current $I=\frac{Q}{T}$ is the formula used to calculate current. The charge in this case is $Q$, and the time period is $T$.We obtain $I=\frac{Q\omega }{2\pi }$ by inserting all the known values into the aforementioned equation.Hence the equivalent current will be $\frac{Q\omega }{2\pi }$

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