CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A non-conducting ring of radius R has charge Q distributed unevenly over it. If it rotates with an angular velocity ω, the equivalent current will be


Open in App
Solution

Step 1: Given data

  1. A non-conducting ring of radius R
  2. Charge Q
  3. Angular velocity ω

Step 2: Formula used

  1. I=QT where Q is the charge, T is the time and I is the current
  2. T=2πω where T is the time period and ω is the angular velocity

Step 3: Find the current

Given that R is the non-conducting ring's radius Q is the charge that has an asymmetric distribution throughout the ring.

It rotates with an angular speed that is determined by.
The charge's rotational period is determined by the formula T=2πω
We've already stated that the amount of charges passing through any fixed place each second is the definition of current I=QT is the formula used to calculate current.
The charge in this case is Q, and the time period is T.
We obtain I=Qω2π by inserting all the known values into the aforementioned equation.
Hence the equivalent current will be Qω2π


flag
Suggest Corrections
thumbs-up
0
BNAT
mid-banner-image