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Question

A normal woman whose father was colour blind marries a colourblind man. What percentage of girls born to these parents would be colourblind.


A
100%
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B
75%
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C
50%
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D
25%
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Solution

The correct option is C $$50\%$$
Xh represents the X affected Colorblind gene. Hence a colorblind will have XhY chromosomes whereas a carrier female will have XhX chromosomes.
Their daughter will have the following chromsome combinations: XhX (Carrier), XhXh (Colorblind). Hence, 50% of the daughters will be colorblind.

So, the correct answer is '50%'.

Biology

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