Question

A normal woman whose father was colour blind marries a colourblind man. What percentage of girls born to these parents would be colourblind.

• A. $100\%$
• B. $75\%$
• C. $50\%$
• D. $25\%$

Answer 1

The correct option is C $50\%$

Xh represents the X affected Colorblind gene. Hence a colorblind will have XhY chromosomes whereas a carrier female will have XhX chromosomes.

Their daughter will have the following chromsome combinations: XhX (Carrier), XhXh (Colorblind). Hence, 50% of the daughters will be colorblind.

So, the correct answer is '50%'.