Question

A nucleus ${}_{11}^{24}Na$ is β-radioactive. Write the equation representing β-decay.

• A. ${}_{11}^{24}Na\to {}_{12}^{23}Mg+{}_{-1}^{1}e$
• B. ${}_{11}^{24}Na\to {}_{12}^{24}Mg+{}_{-1}^{0}e$
• C. ${}_{11}^{24}Na\to {}_{11}^{23}Mg+{}_{-1}^{1}e$
• D. ${}_{11}^{24}Na\to {}_{11}^{24}Mg+{}_1^{0}e$

Answer 1

The correct option is B ${}_{11}^{24}Na\to {}_{12}^{24}Mg+{}_{-1}^{0}e$

${}_{11}^{24}Na\to {}_{12}^{24}Mg+{}_{-1}^{0}e$

This is an example of beta negative decay, here one neutron decayed in proton, keeping the mass number same but increasing the atomic number is $1$.